A torque of 30 N-m is acting on a wheel of mass 5 kg and moment of inertia 2 kg-m 2 .
If wheel starts rotating from rest then, its angular displacement in 10 seconds will be :
Text Solution
Verified by ExpertsThe correct answer is:
D
τ = Ια
30 = 2 × α
⇒ α = 15 rad/sec 2
From equation of angular motion
θ = ω 0 t + 
= 0 + 
× 15 × 10 × 10 = 750 rad
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